设f(a)=f(b)=0,|∫01f’(x)dx|=1,f’(x)∈C[a,b]. 求∫abxf(x)f’(x)dx;

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问题 设f(a)=f(b)=0,|∫01f’(x)dx|=1,f’(x)∈C[a,b].
求∫abxf(x)f’(x)dx;

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答案abxf(x)f’(x)dx=[*]∫abxdf2(x)=[*]f2(x)|ab-[*]∫abf2(x)dx=[*]

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