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  3. ∫0π/2dx/(cos+2sinx)2．

∫0π/2dx/(cos+2sinx)2．

admin2022-10-25  27
问题 ∫0π/2dx/(cos+2sinx)2．
选项
答案∫0π/2dx/(cosx+2sinx)2=∫0π/2sec2xdx/(1+2tanx)2=1/2∫0π/2d(1+2tanx)/(1+2tanx)2=-1/2(1+2tanx)｜-1/2(0-1)=1/2．
解析
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考研数学三

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