∫-π/2π/2(cosx/(2+sinx)+x2sinx)dx．

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问题 ∫_-π/2^π/2(cosx/(2+sinx)+x²sinx)dx．

选项

答案∫_-π/2^π/2(cosx/(2+sinx)+x²sinx)dx=∫_-π/2^π/2cosx/(2+sinx)dx=∫_-π/2^π/2d(2+sinx)/(2+sinx)=ln(1+sinx)｜_-π/2^π/2=ln3．

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考研数学三

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