Complete the notes below. Write NO MORE THAN THREE WORDS for each answer.

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问题 Complete the notes below.
Write NO MORE THAN THREE WORDS for each answer.

选项

答案(at)Studio Theatre /(the)Studio Theatre /(at)Studio Theater /(the)Studio Theater

解析

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本试题收录于：雅思听力题库雅思（IELTS）分类

雅思听力

雅思（IELTS）

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Complete the notes below. Write NO MORE THAN THREE WORDS for each answer.

雅思听力

雅思（IELTS）

Physicistsrejectedtheinnovativeexperimentaltechniquebecause,althoughit(i)____someproblems,italsoproducednew(ii)_

Inrecentdecades,scholarsofAmericanliteraturehaveskillfullyrevealedauthors’simultaneousaccommodationandresistancet

ElizabethBishop’sCompletePoems(1927-1979)hascometoseemtomostofitsreaderssoachievedandsufficientasalife’swork

Tellmeaboutafamouspersonwhoyouparticularlyadmire.Youshouldsay:whothepersonis(was)andwhytheyare(were)famo

Describeaforeignfestivalthatyoulike.Youshouldsay:whatthefestivaliswhenandwherethefestivaltakesplacewhatpeo

Withtheincreaseinsecurityawareness,securitymonitorsarepoppingupinsomeplaces.Someareveryuseful,likethemonitor

Youshouldspendabout20minutesonthistask.YouandyourfamilyarelivinginrentedaccommodationinanEnglish-speakin

Somepeoplesayitismoreimportanttoplanttreesinopenspacesintownsandcitiesthanbuildmorehousing.Towhatextentd

Questions28-29Completethenotes,whichshowhowtheapproachestodefining’talent’havechanged.ChooseONEorTWOWORDSfro

Theaveragenumberofsharkscaughtinnetseachyearis

刚性防水屋面是指用()等材料作防水层，依靠混凝土自身的密实性，并采取一定的构造措施达到防水目的的屋面。

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新建、扩建和改建的各类房屋建筑工程和市政基础设施工程的竣工验收，均应按()规定进行备案。

有如下程序： main() {char ch[2][5]={"6937","8254"}，*p[2]； int i,j，s=0； for(i=0；i＜2；i++)p[i]=ch[i]； for(i=0；i＜2；i++) for(j=0；p[i][j]!=’

HalfoftheBritishworkforceregularlylistentomusiconthejob.

Georgehaddifficultyinswimmingacrossthelake,buthefinallysucceededonhisfourth______.

Nobodywasclearabouthowexactlyhehadmanagedto______suchavastamountofmoneyinsuchashorttime.

Doctor’sorders;LetchildrenjustplayA)Imagineadrugthatcouldenhanceachild’screativityandcriticalthinking.Imag

有如下程序：　main()　{char　ch[2][5]={"6937","8254"}，*p[2]；　int　i,j，s=0；　for(i=0；i＜2；i++)p[i]=ch[i]；　for(i=0；i＜2；i++)　for(j=0；p[i][j]!=’