The numbers 3, 10, 17, 24, 31 and 38 are the first six terms of an infinite sequence in which each term after first is 7 greater

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问题 The numbers 3, 10, 17, 24, 31 and 38 are the first six terms of an infinite sequence in which each term after first is 7 greater than the preceding term. What is the 45th term of the sequence?

选项 A、308
B、311
C、312
D、315
E、318

答案B

解析题目中的序列是一个等差数列a₁=3，公差d=7，那么a₄₅=a₁+(45-1)×7=311。

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The numbers 3, 10, 17, 24, 31 and 38 are the first six terms of an infinite sequence in which each term after first is 7 greater

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