2. 外语
  3. In a certain card game, an ace counts one point, face cards count ten points, and all other cards count their face values. A pla

In a certain card game, an ace counts one point, face cards count ten points, and all other cards count their face values. A pla

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问题 In a certain card game, an ace counts one point, face cards count ten points, and all other cards count their face values. A player must play at least one card on each turn, and his score on a turn is determined by the total point value of the cards played. If a player holds the cards shown above’ one heart ace, one club 2, one diamond 4, one heart 6 and one heart 8), how many different point totals are possible for him on his next turn?
选项 A、5
B、22
C、10
D、20
E、21
答案E
解析 题目首先告诉你如何计算牌的点数，A(ace)算一点，花牌(J，Q，K为face cards)算十点，其他牌则是牌面上有几点就算几点，比如说红桃4就算4点，黑桃8为8点。牌手每一轮至少要出1张牌，现在牌手一共有5张牌(一张红桃ace，一张梅花2，一张方块4，一张红桃6和一张黑桃8)，题目问他下一轮出牌可能共有多少点?他下一轮出牌，可能出一张，也可能出2张，3张，4张或者5张全部出，单出1张就有1，2，4，6，8点，如果出两张，那么就可能得到3，5，7，9，6，8，10，12，14点；已经出现了重复的点数。仔细观察，这道题中最后得到的结果是连续的数字。5张牌点数最多为l+2+4+6+8=21点，最少为1点，因此下一轮牌手出牌的点数有21种。正确答案为E。
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