首页
外语
计算机
考研
公务员
职业资格
财经
工程
司法
医学
专升本
自考
实用职业技能
登录
外语
Which of the following sentences contains subjunctive mood?
Which of the following sentences contains subjunctive mood?
admin
2022-10-15
90
问题
Which of the following sentences contains subjunctive mood?
选项
A、Lucy insisted that her son get home before 5 o’clock.
B、She used to drive to work, but now she takes the city metro.
C、Walk straight ahead, and don’t turn till the second traffic lights.
D、Paul will cancel his flight if he cannot get his visa by Friday.
答案
A
解析
虚拟语气题。表示“命令、建议、要求、提议、坚持”等意义的动词后面若接宾语从句,从句要用虚拟语气,其谓语部分要用“should+动词原形”的形式,其中should可省略,因此A为答案。其他几句均未使用虚拟语气。
转载请注明原文地址:https://www.kaotiyun.com/show/eCkK777K
0
专业英语四级
相关试题推荐
Whichofthefollowingsentenceshasasubjectcomplement?
Whichofthefollowingsentencesexpressesapassivemeaning?
WhichofthefollowingsentencesexpressesREQUEST?
Itisnot______muchthelanguageasthebackgroundthatmakesthebookdifficulttounderstand.
Afive-year-oldboycanspeaktwoforeignlanguages,______surprisesallthepeoplepresent.
[A]astonishment[B]deeply[C]employed[D]scare[E]earnest[F]amuse[G]lying[H]removed[I]significant[J]discovery[K]pursue[L]u
[A]astonishment[B]deeply[C]employed[D]scare[E]earnest[F]amuse[G]lying[H]removed[I]significant[J]discovery[K]pursue[L]u
Thedinnerpartytheylookedforwardto______atlast.
IsTalentanImportantFactorinLearningaForeignLanguage?Whenpeopletrytoexpresstheirviewsontheimportanceofgi
PersonA:Shallwegetsomedinnertonight?PersonB:Thatsoundslikefun.Inthedialogueabove,PersonAis________.
随机试题
女,50岁。因子宫肌瘤行全子宫切防术。术中医生发现患者左侧卵巢有病变应切除,在未征得患者及其家属同意的情况下,将左侧卵巢与子宫一并切除。术后患者恢复良好。该案例中,医生违背的临床诊疗伦理原则是
对于含有聚山梨酯的药物,其防腐能力不会受到破坏的是
某运营商新建光缆线路工程初步设计已完成,工程估算价为2500万元,通过招标确定了一家施工单位,并委托一家监理单位对本工程实施监理。中标施工单位做好了充分准备,在收到开工令后,工程顺利开工。本工程直埋部分与一条地下自来水管交越,部分路段采用立杆架空敷设;工
2003年2月,张某按市场价格出租个人所有的居民住房,取得租金收入500元,则其应纳的房产税税额为20元。()
乘坐火车过程中,导游要注意()。
Inwriting,______willgivestudentstheopportunitytoselectfromthelistthoseusefulideastobeincludedintheirwriting
《种子法》规定,种子贮备的具体办法由()规定。
若用SQL命令检索所有比“刘宁”基本工资多的职工记录,下列语句正确的是()。
以下关于删除表中记录的描述,正确的是( )。
有以下程序voidfun(double*p1,double*p2,double*s){s=(double*)calloc(1,sizeof(double));*s=*p1+*(p2+1);)
最新回复
(
0
)