函数f(x)＝2x3－9x2＋12x－3的驻点为________．

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问题函数f(x)＝2x³－9x²＋12x－3的驻点为________．

选项

答案x₁＝1，x₂＝2

解析

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本试题收录于：数学题库普高专升本分类

数学

普高专升本

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函数f(x)＝2x3－9x2＋12x－3的驻点为________．

数学

普高专升本

若=5，则a=，b=．

证明：当｜x｜≤2时，｜3x-x3｜≤2。

证明：当｜x｜≤1时，则｜4x-x4｜≤5成立。

设b>a>0，证明：∫abdy∫ybf(x)e2x+ydx=∫ab(e3x-e2x+a)f(x)dx。

Haveyou【B1】askedyourselfwhychildrengotoschool?Youwillprobablysaythattheygo【B2】theirownlanguagea

Haveyou【B1】askedyourselfwhychildrengotoschool?Youwillprobablysaythattheygo【B2】theirownlanguagea

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设b>a>0，证明：∫abdy∫ybf(x)e2x+ydx=∫ab(e3x-e2x+a)f(x)dx。

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