2. 考研
  3. 设f(x)连续，证明：∫0x[∫0tf(u)du]dt=∫0xf(t)(x-t)dt．

设f(x)连续，证明：∫0x[∫0tf(u)du]dt=∫0xf(t)(x-t)dt．

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问题 设f(x)连续，证明：∫0x[∫0tf(u)du]dt=∫0xf(t)(x-t)dt．
选项
答案令F(x)=∫0xf(t)dt，则F’(x)=f(x)，于是∫0x[∫0tf(u)du]dt=∫0xF(t)dt，∫0xf(t)(x-t)dt=x∫0xf(t)dt-∫0xtf(t)dt=xF(x)-∫0xtdF(t)=xF(x)-tF(t)｜0x+∫0xF(t)dt=∫0xF(t)dt．
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考研数学二

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