首页
外语
计算机
考研
公务员
职业资格
财经
工程
司法
医学
专升本
自考
实用职业技能
登录
外语
A large flower arrangement contains 3 types of flowers: carnations, lilies, and roses. Of all the flowers in the arrangement, 1/
A large flower arrangement contains 3 types of flowers: carnations, lilies, and roses. Of all the flowers in the arrangement, 1/
admin
2022-10-18
77
问题
A large flower arrangement contains 3 types of flowers: carnations, lilies, and roses. Of all the flowers in the arrangement, 1/2 are carnations, 1/3 are lilies, and 1/6 are roses. The total price of which of the 3 types of flowers in the arrangement is the greatest?
(1) The prices per flower for carnations, lilies, and roses are in the ratio 1:3:4, respectively.
(2) The price of one rose is $0. 75 more than the price of one carnation, and the price of one rose is $0. 25 more than the price of one lily.
选项
A、Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B、Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C、BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D、EACH statement ALONE is sufficient.
E、Statements (1) and (2) TOGETHER are NOT sufficient.
答案
A
解析
Let T be the total number of flowers, and let $C, $L,and $R be the cost, respectively, of one carnation, one lily, and one rose.
(1) We are given that L = 3C (because C:L is 1:3) and R = AC (because C:R is 1:4). The table below shows the total price for each type of flower.
From the table it is clear that lilies have the greatest total cost; SUFFICIENT.
(2) We are given that R = 0.75 + C and R = 0.25 + L. To simplify matters, we can use these equations to express each of the variables C, L, and R in terms of a single fixed variable, for example, C= R- 3/4 and L = R-1/4. This will allow us to replace all appearances of C, L, and R with appearances of R only, thereby reducing by two the number of variables that have to be dealt with. The table below shows, for two values of T and R, the total price for each type of flower.
From the table it is clear that the type of flower having the greatest total cost can vary; NOT sufficient.
The correct answer is A;
statement 1 alone is sufficient.
转载请注明原文地址:https://www.kaotiyun.com/show/JttO777K
本试题收录于:
GMAT QUANTITATIVE题库GMAT分类
0
GMAT QUANTITATIVE
GMAT
相关试题推荐
Concerningmoneyoranythingelse,conflictsbetweenhusbandandwifeusuallyreflectapowerstruggle.Conflictsbetweenparent
Doyouknowinsurance(保险)?Buyinginsuranceisameansbywhichpeoplecanprotectthemselves【C1】______largelosses.Protection
Acompletelynewsituationislikelyto______whentheschoolleavingageisraisedto16.
TheChinesehaveusedamethodcalledacupuncturetohelpperformoperationsforabout4,000yearswithoutputtingthepatient
Whenwetalkaboutintelligence,wedonotmeantheabilitytogetgoodscoresoncertainkindsoftestsoreventheabilityto
Inmakingmarketinvestigation,oneshould______.Allthefollowingarechannelstogetmarketinformationexcept______.
Whenweplaytenniswehaveto______.Whatisofthegreatestimportancetoafootballteamis______.
Ifaandbareoddintegers,whichofthefollowingisaneveninteger?
ThefirstpeopletoinhabitNorthAmericacamefromAsia.Scientistshadhypothesizedthatthesepeopletraveledacrossanow-su
Anthropologywasmuchmorethan______forthenovelistZoraNealeHurston:shestudiedatBarnardCollegewithFranzBoas,whoi
随机试题
TheHappinessInstituteYoudon’tneedmillionstobehappy.AttheHappinessInstituteinAustralia,acoupleofhundredd
患者,男,62岁,进行性排尿困难,夜尿次数增多,直肠指诊发现前列腺明显肿大,最可能的诊断是
背景资料某光缆线路工程采用直埋敷设方式,途中需穿越生态环境脆弱的国家级生态保护区,部分路段沿电气化铁路敷设。施工单位对施工方案进行了策划,编制了详细的施工组织设计,工程顺利开工。测试中发现部分光缆对地绝缘不合格,且光纤接续衰减
构成投资组合的证券甲和证券乙,其标准差分别为12%和8%。在等比例投资的情况下,如果两种证券的相关系数为1,该组合的标准差为10%;如果两种证券的相关系数为-1,则该组合的标准差为2%。( )
国有文物不可以出境展览。()
制订课程计划的首要问题是()
19世纪波兰音乐最杰出的代表人物是()。
网络时代是一个“信息过剩而注意力稀缺”的时代,以网络为基础的当代经济的本质是“注意力经济”,在这种经济形态中,最重要的资源是注意力,因此在互联网上如何吸引注意力成为一个非常重要的问题。网络时代对注意力的经济价值的强调无疑是必需的,但如果忽视了对吸引注意力的
Dopeoplegethappierormorefoul-temperedastheyage?Stereotypesofirritableneighbors【B1】______,scientistshavebeentryi
域表达式{ab|R(ab)∧R(ba)}转换成为等价的关系代数表达式,所列出的式子中(47)是不正确的。SQL中集合成员资格的比较操作“元组NOT IN(集合)”中的“NOT IN”与(48)操作符等价。SQL中涉及属性AGE是甭是空值的比较操作,写法(4
最新回复
(
0
)